X^2+y^2=169(12,5)

Solution for X^2+y^2=169(12,5) equation:

X^2+X^2=169(12.5)

We move all terms to the left:

X^2+X^2-(169(12.5))=0

We add all the numbers together, and all the variables

2X^2-2112.5=0

a = 2; b = 0; c = -2112.5;
Δ = b2-4ac
Δ = 02-4·2·(-2112.5)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-130}{2*2}=\frac{-130}{4}
=-32+1/2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+130}{2*2}=\frac{130}{4}
=32+1/2
$